移动网络题库诺西产品专用知识在线考试题2组

101. How many TDMA frames consist of a GPRS multiframe?

A、26

B、51

C、52

D、1036

答案：C

102. Which logical channel is used to transfer signaling messages such as resource reallocation?

A、PDTCH

B、PTCCH

C、PACCH

D、PBCCH

答案：C

103. Which logical channel is used to send RACH bust on uplink and TAs on downlink?

A、PDTCH

B、PTCCH

C、PACCH

D、PBCCH

答案：B

104. Which parameter is used by GPRS Tunnelling protocol between GSNs to identify a PDP context?

A、NSAPI

B、TLLI

C、SAPI

D、TEID

答案：D

105. Which of following interface are not using CCS7 protocol?

A、Gn

B、Gd

C、Gs

D、Gr

答案：A

106. When a mobile of B class is on the state of standby, what MM information is registered in SGSN?

A、LAI

B、CI

C、RAI

D、None

答案：C

107. What can MS do when it is standby state?

A、Transfer data packets

B、Receive PS or CS paging

C、Do nothing

D、Cell update

答案：B

108. What could a MS do when its state changes from idle to ready?

A、Power on

B、PDP context activation

C、GPRS attach

D、Transferring packets

答案：C

109. When does a MS get IP address?

A、After MS finishes GPRS attach

B、After MS finishes PDP context activate procedure

C、After MS requests RA update

D、After MS finishes Cell update

答案：B

110. Old SGSN can get new SGSN’s IP address by communicating to __________ when a MS requests inter_SGSN RA update.

A、MS

B、GGSN

C、DNS

D、HLR

答案：C

111. SGSN gets GGSN’s IP address by communicating to __________ when a MS makes PDP context activation.

A、PAPU

B、HLR

C、MS

D、DNS

答案：D

112. After GPRS attach, SGSN will assign an identity to identify the MS, what’s it?

A、TMSI

B、P-TMSI

C、TLLI

D、IMSI

答案：B

113. Which of the following is not power control type?

A、BS power increase due to UL signal quality

B、BS power deccrease due to UL signal quality

C、BS power increase due to UL interference

D、BS power increase due to UL signal level

E、BS power deccrease due to UL signal level

答案：C

114. MS is currently served by macrocell with av_rxLev_DL= -75 dBm and av_rxQual_DL=4, MS measures av_rxLev_ncell(cell2) = -76 dBm and av_rxLev_ncell(cell1) = -83 dBm.

A、MS umbrella HO to cell2

B、MS umbrella HO to cell1

C、MS intracell HO

D、MS HO to cell1 due to DL interference

E、MS HO to cell2 due to DL interference

F、MS HO to cell1 due to DL Quality threshold

G、MS HO to cell2 due to DL Quality threshold

答案：C

115. MS is currently served by macrocell with av_rxLev_DL= -75 dBm and av_rxQual_DL=4, MS measures av_rxLev_ncell(cell2) = -75 dBm and av_rxLev_ncell(cell1) = -83 dBm.

A、MS umbrella HO to cell2

B、MS umbrella HO to cell1

C、MS intracell HO

D、MS HO to cell1 due to DL interference

E、MS HO to cell2 due to DL interference

F、MS HO to cell1 due to DL Quality threshold

G、MS HO to cell2 due to DL Quality threshold

答案：E

116. MS is currently served by macrocell with av_rxLev_DL= -82 dBm and av_rxQual_DL=4, MS measures av_rxLev_ncell(cell2) = -82 dBm and av_rxLev_ncell(cell1) = -83 dBm.

A、MS umbrella HO to cell2

B、MS umbrella HO to cell1

C、MS intracell HO

D、MS HO to cell1 due to DL interference

E、MS HO to cell2 due to DL interference

F、MS HO to cell1 due to DL Quality threshold

G、MS HO to cell2 due to DL Quality threshold

答案：G

117. MS is currently served by macrocell with av_rxLev_DL= -73 dBm and av_rxQual_DL=0, MS measures av_rxLev_ncell(cell2) = -75 dBm and av_rxLev_ncell(cell1) = -66 dBm.

A、MS umbrella HO to cell2

B、MS umbrella HO to cell1

C、MS intracell HO

D、MS HO to cell1 due to power budget

E、MS HO to cell2 due to power budget

F、MS HO to cell1 due to DL Level threshold

G、MS HO to cell2 due to DL Level threshold

答案：A

118. MS is currently served by macrocell with av_rxLev_DL= -90 dBm and av_rxQual_DL=0, MS measures av_rxLev_ncell(cell2) = -86 dBm and av_rxLev_ncell(cell1) = -82 dBm.

A、MS umbrella HO to cell2

B、MS umbrella HO to cell1

C、MS intracell HO

D、MS HO to cell1 due to power budget

E、MS HO to cell2 due to power budget

F、MS HO to cell1 due to DL Level threshold

G、MS HO to cell2 due to DL Level threshold

答案：D

119. MS is currently served by macrocell with av_rxLev_DL= -98 dBm and av_rxQual_DL=0, MS measures av_rxLev_ncell(cell2) = -94 dBm and av_rxLev_ncell(cell1) = -91 dBm.

A、MS umbrella HO to cell2

B、MS umbrella HO to cell1

C、MS stays in the current serving cell

D、MS HO to cell1 due to power budget

E、MS HO to cell2 due to power budget

F、MS HO to cell1 due to DL Level threshold

G、MS HO to cell2 due to DL Level threshold

答案：F

120. MS is currently served by macrocell with av_rxLev_DL = -85 dBm and av_rxQual_DL=0, MS measures av_rxLev_ncell(cell2) = -82 dBm and av_rxLev_ncell(cell1) = -80 dBm.

A、MS umbrella HO to cell2

B、MS umbrella HO to cell1

C、MS stays in the current serving cell

D、MS HO to cell1 due to power budget

E、MS HO to cell2 due to power budget

F、MS HO to cell1 due to DL threshold

G、MS HO to cell2 due to DL threshold

答案：C

121. If the enaFastAveHO= yes, what is the first averaging value?

A、-86 dBm

B、-89.8 dBm

C、-95.0 dBm

D、-90.2 dBm

答案：A

122. What is second px/nx value?

A、0/3

B、1/3

C、2/3

D、3/3

答案：C

123. What is first px/nx value?

A、0/3

B、1/3

C、2/3

D、3/3

答案：B

124. What is last averaging value?

A、-86 dBm

B、-89.8 dBm

C、-95.0 dBm

D、-90.2 dBm

答案：C

125. What is first averaging value?

A、-86 dBm

B、-89.8 dBm

C、-95.0 dBm

D、-90.2 dBm

答案：B

126. What is the concept of weighting scheme?

A、To put more weights for the measurements with DTX

B、To put more weights for the measurements without DTX

C、To put more weights for the measurements regardless of DTX status

答案：B

127. What is the averaging window size?

A、Window size=5

B、Window size=4

C、Window size=3

D、Window size=2

答案：B

128. 现网使用COMMON BCCH中主BTS的BCCH必须用（）

A、、EGSM

B、PGSM

C、DCS1800

答案：B

129. （）  频点不能设置SDCCH。

A、、EGSM900

B、PGSM900

C、DCS1800

答案：A

130. GSM小区（CELL）的发射半径控制在35公里内的主要由哪种因素决定 （）

A、时隙定位的问题

B、频率复用方式

C、输出功率不允许超过40W

答案：A

131. 采用分集接收技术，对  （ ）  有较大的改善。

A、上行链路信号

B、下行链路信号

C、上行与下行链路信号

D、以上都不正确

答案：A

132. GSM系统中时间提前量（TA）的一个单位对应空间传播的距离接近  (  )

A、450

B、500

C、550

D、600

答案：C

133. 无线信号在自由空间的衰落情况是：传播距离每增大一倍，信号强度减小（）

A、2dB

B、3dB

C、6dB

D、9dB

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